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163.84=26.3y-y^2
We move all terms to the left:
163.84-(26.3y-y^2)=0
We get rid of parentheses
y^2-26.3y+163.84=0
a = 1; b = -26.3; c = +163.84;
Δ = b2-4ac
Δ = -26.32-4·1·163.84
Δ = 36.33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26.3)-\sqrt{36.33}}{2*1}=\frac{26.3-\sqrt{36.33}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26.3)+\sqrt{36.33}}{2*1}=\frac{26.3+\sqrt{36.33}}{2} $
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